PSLE Shiyun and Opal folded paper stars over two days. On Monday, Shiyun folded 18 paper stars more than Opal. On Tuesday, Shiyun folded another 15 paper stars and Opal folded another 15. At the end of the two days, Shiyun made
58 of the total number of stars. What was the number of paper stars that Shiyun folded?
|
Shiyun |
Opal |
Difference |
Before |
1 u + 18 |
1 u |
18 |
Change |
+ 15 |
+ 15 |
|
After |
1 u + 33 |
1 u + 15 |
18 |
Comparing between Shiyun and Opal in the end |
5 p |
3 p |
2 p |
Difference between the number of paper stars that Shiyun and Opal folded in the end is repeated.
Difference between the number of paper stars that Shiyun and Opal folded in the end
= 5 p - 3 p
= 2 p
Difference between the number of paper stars that Shiyun and Opal folded in the end
= (1 u + 33) - (1 u + 15)
= 1 u + 33 - 1 u - 15
= 33 - 15
= 18
2 p = 18
1 p = 18 ÷ 2 = 9
Number of paper stars that Shiyun folded
= 5 p
= 5 x 9
= 45
Answer(s): 45