PSLE
Dana and Fanny folded paper stars over two days. On Friday, Dana folded 11 paper stars more than Fanny. On Saturday, Dana folded another 34 paper stars and Fanny folded another 6. At the end of the two days, Dana made ⁵₇ of the total number of stars. What was the number of paper stars that Dana folded?

	Dana	Fanny	Difference
Before	1 u + 11	1 u	11
Change	+ 34	+ 6
After	1 u + 45	1 u + 6	39
Comparing between Dana and Fanny in the end	5 p	2 p	3 p

Difference between the number of paper stars that Dana and Fanny folded in the end is repeated.

Difference between the number of paper stars that Dana and Fanny folded in the end
= 5 p - 2 p
= 3 p

Difference between the number of paper stars that Dana and Fanny folded in the end
= (1 u + 45) - (1 u + 6)
= 1 u + 45 - 1 u - 6
= 45 - 6
= 39

3 p = 39

1 p = 39 ÷ 3 = 13

Number of paper stars that Dana folded
= 5 p
= 5 x 13
= 65

Answer(s): 65