PSLE
Gem and Xylia folded paper balls over two days. On Monday, Gem folded 64 paper balls more than Xylia. On Tuesday, Gem folded another 30 paper balls and Xylia folded another 34. At the end of the two days, Gem made ⁷₁₀ of the total number of balls. What was the number of paper balls that Gem folded?

	Gem	Xylia	Difference
Before	1 u + 64	1 u	64
Change	+ 30	+ 34
After	1 u + 94	1 u + 34	60
Comparing between Gem and Xylia in the end	7 p	3 p	4 p

Difference between the number of paper balls that Gem and Xylia folded in the end is repeated.

Difference between the number of paper balls that Gem and Xylia folded in the end
= 7 p - 3 p
= 4 p

Difference between the number of paper balls that Gem and Xylia folded in the end
= (1 u + 94) - (1 u + 34)
= 1 u + 94 - 1 u - 34
= 94 - 34
= 60

4 p = 60

1 p = 60 ÷ 4 = 15

Number of paper balls that Gem folded
= 7 p
= 7 x 15
= 105

Answer(s): 105