PSLE Yen and Pamela folded paper stars over two days. On Monday, Yen folded 36 paper stars more than Pamela. On Tuesday, Yen folded another 20 paper stars and Pamela folded another 28. At the end of the two days, Yen made
58 of the total number of stars. What was the number of paper stars that Pamela folded?
|
Yen |
Pamela |
Difference |
Before |
1 u + 36 |
1 u |
36 |
Change |
+ 20 |
+ 28 |
|
After |
1 u + 56 |
1 u + 28 |
28 |
Comparing between Yen and Pamela in the end |
5 p |
3 p |
2 p |
Difference between the number of paper stars that Yen and Pamela folded in the end is repeated.
Difference between the number of paper stars that Yen and Pamela folded in the end
= 5 p - 3 p
= 2 p
Difference between the number of paper stars that Yen and Pamela folded in the end
= (1 u + 56) - (1 u + 28)
= 1 u + 56 - 1 u - 28
= 56 - 28
= 28
2 p = 28
1 p = 28 ÷ 2 = 14
Number of paper stars that Pamela folded
= 3 p
= 3 x 14
= 42
Answer(s): 42