PSLE At Xavier's fruit stall,
14 of the kiwis were golden and the rest were green. He sold
12 of the total number of kiwis.
25 of the kiwis sold were golden. 135 green kiwis were left. How many golden kiwis did Xavier sell?
|
Golden |
Green |
Total |
Before |
1x5 = 5 u |
3x5 = 15 u |
4x5 = 20 u |
Change |
|
|
- 2x5 = - 10 u |
Comparing green kiwis and golden kiwis sold |
- 2x2 = - 4 u |
- 3x2 = - 6 u |
- 5x2 = - 10 u |
After |
1 u |
9 u |
2x5 = 10 u |
The total number of kiwis is the same. Make the denominators of the total number of kiwis the same.
12 =
24The number of kiwis sold is the repeated identity. Make the number of kiwis sold the same. LCM of 2 and 5 is 10.
9 u = 135
1 u = 135 ÷ 9 = 15
Number of golden kiwis that Xavier sold
= 4 u
= 4 x 15
= 60
Answer(s): 60