PSLE
Opal spent ¹₉ of her money on a blazer and 4 windbreakers. The blazer cost 2 times as much as each windbreaker. Opal spent ⁵₆ of her remaining money on a bracelet. She spent $540 more on the bracelet than on the 4 windbreakers.
(a) What fraction of Opal's money was spent on each windbreaker?
(b) How much money did Opal have at first?
(a)
Cost of 1 windbreaker = 1 u

Cost of 4 windbreakers
= 4 x 1 u
= 4 u

Cost of 1 blazer = 2 u

Cost of 1 blazer and 4 windbreakers
= 2 u + 4 u
= 6 u

Fraction of Opal's money spent on each windbreaker
= ¹₆ x ¹₉
= ¹₅₄

(b)
¹₉ of her money = 6 u
⁸₉ of her money = 8 x 6 u = 48 u

Opal's remaining money = 48 u

Cost of the bracelet
= ⁵₆ x 48 u
= 40 u

Amount that Opal spent more on the bracelet than on the 4 windbreakers
= 40 u - 4 u
= 36 u

36 u = 540

1 u = 540 ÷ 36 = 15

⁹₉ of her money = 9 x 6 u = 54 u

Amount that Opal had at first
= 54 u
= 54 x 15
= $810

Answer(s): (a) ¹₅₄ ; (b) $810