PSLE At a sale, Gabriel bought 11 cups of the same kind. His sister bought 8 such cups. She also bought 5 bowls at $7.90 each. Altogether, she spent $10.70 more than Gabriel. What was the total amount of money Gabriel and his sister spent?
|
Gabriel |
His sister |
Items bought
|
11 cups
|
8 cups + 5 bowls = 8 cups + 39.50 |
Comparing the amounts paid |
|
$10.70 more |
Amount that his sister spent on 5 bowls
= 5 x 7.90
= $39.50
Let the cost of 1 cup be 1 C.
If Gabriel's sister spent $10.70 less, each would pay the same amount.
11 C + 10.70 = 8 C + 39.50 - 10.70
11 C - 8 C = 39.50 - 10.70
3 C = 28.80
1 C = 28.80 ÷ 3 = 9.60
Total amount that Gabriel and his sister spent
= 11 C + 8 C + 39.50
= 19 C + 39.50
= 19 x 9.60 + 39.50
= 182.40 + 39.50
= $221.90
Answer(s): $221.90