PSLE A fruit stall sold grapefruits at 90¢ and papayas at 60¢ each. Fiona bought some grapefruits and Esther bought some papayas from the stall. Fiona spent $1.20 more than Esther, but had 4 fruits fewer than Esther.
- How many grapefruits did Fiona buy?
- How much did Esther spend on the papayas?
|
Grapefruits |
Papayas |
Number |
1 u |
1 u + 4 |
Value |
0.9 |
0.6 |
Total value |
0.9 u |
0.6 u + 2.4 |
(a)
Number of grapefruits that Fiona bought = 1 u
Number of papayas that Esther bought = 1 u + 4
Amount that Fiona paid = 0.9 x 1 u = 0.9 u
Amount that Esther paid = 0.6(1 u + 4) = 0.6 u + 2.4
If Esther spent another $1.20, both Esther and Fiona would spend the same amount.
0.9 u = 0.6 u + 2.4 + 1.2
0.9 u - 0.6 u = 2.4 + 1.2
0.3 u = 3.6
1 u = 3.6 ÷ 0.3 = 12
Number of grapefruits that Fiona bought
= 1 u
= 12
(b)
Amount that Esther spent on the papayas
= 0.6 u + 2.4
= 0.6 x 12 + 2.4
= 7.2 + 2.4
= $9.60
Answer(s): (a) 12; (b) $9.60