PSLE
A fruit stall sold guavas at 60¢ and papayas at 40¢ each. Hilda bought some guavas and Hazel bought some papayas from the stall. Hazel spent $0.60 less than Hilda, but had 4 fruits more than Hilda.

1. How many papayas did Hazel buy?
2. How much did Hilda spend on the guavas?

	Guavas	Papayas
Number	1 u	1 u + 4
Value	0.6	0.4
Total value	0.6 u	0.4 u + 1.6

(a)
Number of guavas that Hilda bought = 1 u
Number of papayas that Hazel bought = 1 u + 4

Amount that Hilda paid = 0.6 x 1 u = 0.6 u
Amount that Hazel paid = 0.4(1 u + 4) = 0.4 u + 1.6

If Hazel spent another $0.60, both Hazel and Hilda would spend the same amount.

0.6 u = 0.4 u + 1.6 + 0.6
0.6 u - 0.4 u = 1.6 + 0.6
0.2 u = 2.2

1 u = 2.2 ÷ 0.2 = 11

Number of papayas that Hazel bought
= 1 u + 4
= 11 + 4
= 15

(b)
Amount that Hilda spent on the guavas
= 0.6 u 
= 0.6 x 11 
= $6.60

Answer(s): (a) 11; (b) $6.60