PSLE
A fruit stall sold papayas at 90¢ and limes at 60¢ each. Gwen bought some papayas and Min bought some limes from the stall. Gwen spent $0.90 more than Min, but had 2 fruits fewer than Min.

1. How many papayas did Gwen buy?
2. How much did Min spend on the limes?

	Papayas	Limes
Number	1 u	1 u + 2
Value	0.9	0.6
Total value	0.9 u	0.6 u + 1.2

(a)
Number of papayas that Gwen bought = 1 u
Number of limes that Min bought = 1 u + 2

Amount that Gwen paid = 0.9 x 1 u = 0.9 u
Amount that Min paid = 0.6(1 u + 2) = 0.6 u + 1.2

If Min spent another $0.90, both Min and Gwen would spend the same amount.

0.9 u = 0.6 u + 1.2 + 0.9
0.9 u - 0.6 u = 1.2 + 0.9
0.3 u = 2.1

1 u = 2.1 ÷ 0.3 = 7

Number of papayas that Gwen bought
= 1 u
= 7

(b)
Amount that Min spent on the limes
= 0.6 u + 1.2
= 0.6 x 7 + 1.2
= 4.2 + 1.2
= $5.40

Answer(s): (a) 7; (b) $5.40