PSLE A fruit stall sold pears at 60¢ and oranges at 30¢ each. Esther bought some pears and Gillian bought some oranges from the stall. Esther spent $2.40 more than Gillian, but had 4 fruits fewer than Gillian.
- How many pears did Esther buy?
- How much did Gillian spend on the oranges?
|
Pears |
Oranges |
Number |
1 u |
1 u + 4 |
Value |
0.6 |
0.3 |
Total value |
0.6 u |
0.3 u + 1.2 |
(a)
Number of pears that Esther bought = 1 u
Number of oranges that Gillian bought = 1 u + 4
Amount that Esther paid = 0.6 x 1 u = 0.6 u
Amount that Gillian paid = 0.3(1 u + 4) = 0.3 u + 1.2
If Gillian spent another $2.40, both Gillian and Esther would spend the same amount.
0.6 u = 0.3 u + 1.2 + 2.4
0.6 u - 0.3 u = 1.2 + 2.4
0.3 u = 3.6
1 u = 3.6 ÷ 0.3 = 12
Number of pears that Esther bought
= 1 u
= 12
(b)
Amount that Gillian spent on the oranges
= 0.3 u + 1.2
= 0.3 x 12 + 1.2
= 3.6 + 1.2
= $4.80
Answer(s): (a) 12; (b) $4.80