PSLE A fruit stall sold peaches at 60¢ and limes at 30¢ each. Roshel bought some peaches and Jean bought some limes from the stall. Roshel spent $1.20 more than Jean, but had 6 fruits fewer than Jean.
- How many peaches did Roshel buy?
- How much did Jean spend on the limes?
|
Peaches |
Limes |
Number |
1 u |
1 u + 6 |
Value |
0.6 |
0.3 |
Total value |
0.6 u |
0.3 u + 1.8 |
(a)
Number of peaches that Roshel bought = 1 u
Number of limes that Jean bought = 1 u + 6
Amount that Roshel paid = 0.6 x 1 u = 0.6 u
Amount that Jean paid = 0.3(1 u + 6) = 0.3 u + 1.8
If Jean spent another $1.20, both Jean and Roshel would spend the same amount.
0.6 u = 0.3 u + 1.8 + 1.2
0.6 u - 0.3 u = 1.8 + 1.2
0.3 u = 3
1 u = 3 ÷ 0.3 = 10
Number of peaches that Roshel bought
= 1 u
= 10
(b)
Amount that Jean spent on the limes
= 0.3 u + 1.8
= 0.3 x 10 + 1.8
= 3 + 1.8
= $4.80
Answer(s): (a) 10; (b) $4.80