PSLE
A fruit stall sold lemons at 70¢ and papayas at 40¢ each. Abi bought some lemons and Gillian bought some papayas from the stall. Abi spent $2.80 more than Gillian, but had 2 fruits fewer than Gillian.

1. How many lemons did Abi buy?
2. How much did Gillian spend on the papayas?

	Lemons	Papayas
Number	1 u	1 u + 2
Value	0.7	0.4
Total value	0.7 u	0.4 u + 0.8

(a)
Number of lemons that Abi bought = 1 u
Number of papayas that Gillian bought = 1 u + 2

Amount that Abi paid = 0.7 x 1 u = 0.7 u
Amount that Gillian paid = 0.4(1 u + 2) = 0.4 u + 0.8

If Gillian spent another $2.80, both Gillian and Abi would spend the same amount.

0.7 u = 0.4 u + 0.8 + 2.8
0.7 u - 0.4 u = 0.8 + 2.8
0.3 u = 3.6

1 u = 3.6 ÷ 0.3 = 12

Number of lemons that Abi bought
= 1 u
= 12

(b)
Amount that Gillian spent on the papayas
= 0.4 u + 0.8
= 0.4 x 12 + 0.8
= 4.8 + 0.8
= $5.60

Answer(s): (a) 12; (b) $5.60