PSLE A fruit stall sold pomegranates at 70¢ and papayas at 40¢ each. Xylia bought some pomegranates and Shannon bought some papayas from the stall. Shannon spent $1.20 less than Xylia, but had 6 fruits more than Xylia.
- How many papayas did Shannon buy?
- How much did Xylia spend on the pomegranates?
|
Pomegranates |
Papayas |
Number |
1 u |
1 u + 6 |
Value |
0.7 |
0.4 |
Total value |
0.7 u |
0.4 u + 2.4 |
(a)
Number of pomegranates that Xylia bought = 1 u
Number of papayas that Shannon bought = 1 u + 6
Amount that Xylia paid = 0.7 x 1 u = 0.7 u
Amount that Shannon paid = 0.4(1 u + 6) = 0.4 u + 2.4
If Shannon spent another $1.20, both Shannon and Xylia would spend the same amount.
0.7 u = 0.4 u + 2.4 + 1.2
0.7 u - 0.4 u = 2.4 + 1.2
0.3 u = 3.6
1 u = 3.6 ÷ 0.3 = 12
Number of papayas that Shannon bought
= 1 u + 6
= 12 + 6
= 18
(b)
Amount that Xylia spent on the pomegranates
= 0.7 u
= 0.7 x 12
= $8.40
Answer(s): (a) 12; (b) $8.40