PSLE
Betty and Diana each had a plate of dough of the same mass for making croissants. The same mass of dough was used for each croissant. Betty made 37 croissants and had 270 g of dough left. Diana made 17 croissants and had 1.07 kg of dough left.

1. What was the mass of dough needed for each croissant?
2. With the remaining dough from both girls, how many more such croissants can be made at most? 

(a)
Difference between the number of croissants made by Betty and Diana
= 37 - 17
= 20

1 kg = 1000 g
1.07 kg = 1.07 x 1000 = 1070 g

Difference between the remaining dough left by Diana and Betty
= 1070 - 270
= 800 g

Mass of 20 croissants = 800 g

Mass of 1 croissant
= 800 ÷ 20
= 40 g

(b)
Total remaining dough left
= 1070 + 270
= 1340 g

Sets of 40 g
= 1340 ÷ 40
= 33 r 20

Number of croissants = 33

Answer(s): (a) 40 g; (b) 33