PSLE
Betty and Jean each had a plate of dough of the same mass for making croissants. The same mass of dough was used for each croissant. Betty made 34 croissants and had 170 g of dough left. Jean made 14 croissants and had 1.07 kg of dough left.

1. What was the mass of dough needed for each croissant?
2. With the remaining dough from both girls, how many more such croissants can be made at most? 

(a)
Difference between the number of croissants made by Betty and Jean
= 34 - 14
= 20

1 kg = 1000 g
1.07 kg = 1.07 x 1000 = 1070 g

Difference between the remaining dough left by Jean and Betty
= 1070 - 170
= 900 g

Mass of 20 croissants = 900 g

Mass of 1 croissant
= 900 ÷ 20
= 45 g

(b)
Total remaining dough left
= 1070 + 170
= 1240 g

Sets of 45 g
= 1240 ÷ 45
= 27 r 25

Number of croissants = 27

Answer(s): (a) 45 g; (b) 27