PSLE
Three boys, Eli, Lee and Roy had the same number of notes. Eli and Lee each had of mix of $20-notes and $10-notes. Eli had 4 $10-notes while Lee had 10 $10-notes. Roy had only $20-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Eli and Lee's notes? 
3. Lee used all his $20-notes to buy a gift. He then had $260 less than Roy. How many $20-notes did Roy have?

(a)
The three boys had the same number of notes.
$10-notes have a lower denomination than $20-notes.

Since Roy had only $20-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 10 - 4
= 6

Difference in the value of $20-notes and $10-notes
= 20 - 10
= $10

Difference in the total value of Eli's and Lee's notes
= 6 x 10
= $60

(c)
Value of $10-notes that Lee had left
= 10 x 10
= $100

Total value that Roy had
= 260 + 100
= $360

Number of $20-notes that Roy had
= 360 ÷ 20
= 18

Answer(s): (a) Roy; (b) $60; (c) 18