PSLE Three boys, Lee, Zac and Hal had the same number of notes. Lee and Zac each had of mix of $10-notes and $2-notes. Lee had 5 $2-notes while Zac had 23 $2-notes. Hal had only $10-notes.
- Of the three boys, who had the most money?
- What was the difference in the total value of Lee and Zac's notes?
- Zac used all his $10-notes to buy a present. He then had $244 less than Hal. How many $10-notes did Hal have?
(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $10-notes.
Since Hal had only $10-notes, he had the most money.
(b)
Difference in the number of notes of different values
= 23 - 5
= 18
Difference in the value of $10-notes and $2-notes
= 10 - 2
= $8
Difference in the total value of Lee's and Zac's notes
= 18 x 8
= $144
(c)
Value of $2-notes that Zac had left
= 23 x 2
= $46
Total value that Hal had
= 244 + 46
= $290
Number of $10-notes that Hal had
= 290 ÷ 10
= 29
Answer(s): (a) Hal; (b) $144; (c) 29