PSLE
Three men, Don, Ken and Ace had the same number of notes. Ken and Don each had of mix of $50-notes and $10-notes. Ken had 3 $10-notes while Don had 17 $10-notes. Ace had only $50-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Ken and Don's notes? 
3. Don used all his $50-notes to buy a souvenir. Ace then had $1080 more than Don. How many $50-notes did Ace have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $50-notes.

Don had more $10-notes than Ken while Ace had only the $50-notes.  

Since Don had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 17 - 3
= 14

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Difference in the total value of Ken's and Don's notes
= 14 x 40
= $560

(c)
Value of $10-notes that Don had left
= 17 x 10
= $170

Total value that Ace had
= 1080 + 170
= $1250

Number of $50-notes that Ace had
= 1250 ÷ 50
= 25

Answer(s): (a) Don; (b) $560; (c) 25