PSLE
Three boys, Ace, Nat and Kai had the same number of notes. Ace and Nat each had of mix of $20-notes and $2-notes. Ace had 13 $2-notes while Nat had 19 $2-notes. Kai had only $20-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Ace and Nat's notes? 
3. Nat used all his $20-notes to buy a present. He then had $442 less than Kai. How many $20-notes did Kai have?

(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $20-notes.

Since Kai had only $20-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 19 - 13
= 6

Difference in the value of $20-notes and $2-notes
= 20 - 2
= $18

Difference in the total value of Ace's and Nat's notes
= 6 x 18
= $108

(c)
Value of $2-notes that Nat had left
= 19 x 2
= $38

Total value that Kai had
= 442 + 38
= $480

Number of $20-notes that Kai had
= 480 ÷ 20
= 24

Answer(s): (a) Kai; (b) $108; (c) 24