PSLE
Three men, Ace, Nat and Ben had the same number of notes. Nat and Ace each had of mix of $20-notes and $10-notes. Nat had 9 $10-notes while Ace had 14 $10-notes. Ben had only $20-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Nat and Ace's notes? 
3. Ace used all his $20-notes to buy a present. Ben then had $320 more than Ace. How many $20-notes did Ben have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $20-notes.

Ace had more $10-notes than Nat while Ben had only the $20-notes.  

Since Ace had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 14 - 9
= 5

Difference in the value of $20-note and $10-note
= 20 - 10
= $10

Difference in the total value of Nat's and Ace's notes
= 5 x 10
= $50

(c)
Value of $10-notes that Ace had left
= 14 x 10
= $140

Total value that Ben had
= 320 + 140
= $460

Number of $20-notes that Ben had
= 460 ÷ 20
= 23

Answer(s): (a) Ace; (b) $50; (c) 23