PSLE
Three boys, Zac, Abe and Ken had the same number of notes. Zac and Abe each had of mix of $10-notes and $2-notes. Zac had 6 $2-notes while Abe had 18 $2-notes. Ken had only $10-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Zac and Abe's notes? 
3. Abe used all his $10-notes to buy a present. He then had $254 less than Ken. How many $10-notes did Ken have?

(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $10-notes.

Since Ken had only $10-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 18 - 6
= 12

Difference in the value of $10-notes and $2-notes
= 10 - 2
= $8

Difference in the total value of Zac's and Abe's notes
= 12 x 8
= $96

(c)
Value of $2-notes that Abe had left
= 18 x 2
= $36

Total value that Ken had
= 254 + 36
= $290

Number of $10-notes that Ken had
= 290 ÷ 10
= 29

Answer(s): (a) Ken; (b) $96; (c) 29