PSLE
Three men, Ray, Abe and Jed had the same number of notes. Abe and Ray each had of mix of $50-notes and $10-notes. Abe had 5 $10-notes while Ray had 18 $10-notes. Jed had only $50-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Abe and Ray's notes? 
3. Ray used all his $50-notes to buy a gift. Jed then had $1120 more than Ray. How many $50-notes did Jed have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $50-notes.

Ray had more $10-notes than Abe while Jed had only the $50-notes.  

Since Ray had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 18 - 5
= 13

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Difference in the total value of Abe's and Ray's notes
= 13 x 40
= $520

(c)
Value of $10-notes that Ray had left
= 18 x 10
= $180

Total value that Jed had
= 1120 + 180
= $1300

Number of $50-notes that Jed had
= 1300 ÷ 50
= 26

Answer(s): (a) Ray; (b) $520; (c) 26