PSLE Three boys, Ken, Abe and Gus had the same number of notes. Ken and Abe each had of mix of $5-notes and $2-notes. Ken had 12 $2-notes while Abe had 17 $2-notes. Gus had only $5-notes.
- Of the three boys, who had the most money?
- What was the difference in the total value of Ken and Abe's notes?
- Abe used all his $5-notes to buy a present. He then had $86 less than Gus. How many $5-notes did Gus have?
(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $5-notes.
Since Gus had only $5-notes, he had the most money.
(b)
Difference in the number of notes of different values
= 17 - 12
= 5
Difference in the value of $5-notes and $2-notes
= 5 - 2
= $3
Difference in the total value of Ken's and Abe's notes
= 5 x 3
= $15
(c)
Value of $2-notes that Abe had left
= 17 x 2
= $34
Total value that Gus had
= 86 + 34
= $120
Number of $5-notes that Gus had
= 120 ÷ 5
= 24
Answer(s): (a) Gus; (b) $15; (c) 24