PSLE
Three men, Eli, Kai and Abe had the same number of notes. Kai and Eli each had of mix of $100-notes and $10-notes. Kai had 2 $10-notes while Eli had 14 $10-notes. Abe had only $100-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Kai and Eli's notes? 
3. Eli used all his $100-notes to buy a present. Abe then had $1860 more than Eli. How many $100-notes did Abe have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $100-notes.

Eli had more $10-notes than Kai while Abe had only the $100-notes.  

Since Eli had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 14 - 2
= 12

Difference in the value of $100-note and $10-note
= 100 - 10
= $90

Difference in the total value of Kai's and Eli's notes
= 12 x 90
= $1080

(c)
Value of $10-notes that Eli had left
= 14 x 10
= $140

Total value that Abe had
= 1860 + 140
= $2000

Number of $100-notes that Abe had
= 2000 ÷ 100
= 20

Answer(s): (a) Eli; (b) $1080; (c) 20