PSLE
Three boys, Abe, Kai and Lee had the same number of notes. Abe and Kai each had of mix of $5-notes and $2-notes. Abe had 3 $2-notes while Kai had 19 $2-notes. Lee had only $5-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Abe and Kai's notes? 
3. Kai used all his $5-notes to buy a souvenir. He then had $92 less than Lee. How many $5-notes did Lee have?

(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $5-notes.

Since Lee had only $5-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 19 - 3
= 16

Difference in the value of $5-notes and $2-notes
= 5 - 2
= $3

Difference in the total value of Abe's and Kai's notes
= 16 x 3
= $48

(c)
Value of $2-notes that Kai had left
= 19 x 2
= $38

Total value that Lee had
= 92 + 38
= $130

Number of $5-notes that Lee had
= 130 ÷ 5
= 26

Answer(s): (a) Lee; (b) $48; (c) 26