PSLE
Three boys, Abe, Jed and Rey had the same number of notes. Abe and Jed each had of mix of $5-notes and $2-notes. Abe had 7 $2-notes while Jed had 15 $2-notes. Rey had only $5-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Abe and Jed's notes? 
3. Jed used all his $5-notes to buy a gift. He then had $110 less than Rey. How many $5-notes did Rey have?

(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $5-notes.

Since Rey had only $5-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 15 - 7
= 8

Difference in the value of $5-notes and $2-notes
= 5 - 2
= $3

Difference in the total value of Abe's and Jed's notes
= 8 x 3
= $24

(c)
Value of $2-notes that Jed had left
= 15 x 2
= $30

Total value that Rey had
= 110 + 30
= $140

Number of $5-notes that Rey had
= 140 ÷ 5
= 28

Answer(s): (a) Rey; (b) $24; (c) 28