PSLE
Three boys, Joe, Rey and Ace had the same number of notes. Joe and Rey each had of mix of $20-notes and $2-notes. Joe had 9 $2-notes while Rey had 14 $2-notes. Ace had only $20-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Joe and Rey's notes? 
3. Rey used all his $20-notes to buy a gift. He then had $432 less than Ace. How many $20-notes did Ace have?

(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $20-notes.

Since Ace had only $20-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 14 - 9
= 5

Difference in the value of $20-notes and $2-notes
= 20 - 2
= $18

Difference in the total value of Joe's and Rey's notes
= 5 x 18
= $90

(c)
Value of $2-notes that Rey had left
= 14 x 2
= $28

Total value that Ace had
= 432 + 28
= $460

Number of $20-notes that Ace had
= 460 ÷ 20
= 23

Answer(s): (a) Ace; (b) $90; (c) 23