PSLE
Three men, Lee, Abe and Dan had the same number of notes. Abe and Lee each had of mix of $100-notes and $20-notes. Abe had 2 $20-notes while Lee had 13 $20-notes. Dan had only $100-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Abe and Lee's notes? 
3. Lee used all his $100-notes to buy a present. Dan then had $1540 more than Lee. How many $100-notes did Dan have?

(a)
The three men had the same number of notes.
$20-notes have a lower denomination than $100-notes.

Lee had more $20-notes than Abe while Dan had only the $100-notes.  

Since Lee had the most number of $20-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 13 - 2
= 11

Difference in the value of $100-note and $20-note
= 100 - 20
= $80

Difference in the total value of Abe's and Lee's notes
= 11 x 80
= $880

(c)
Value of $20-notes that Lee had left
= 13 x 20
= $260

Total value that Dan had
= 1540 + 260
= $1800

Number of $100-notes that Dan had
= 1800 ÷ 100
= 18

Answer(s): (a) Lee; (b) $880; (c) 18