PSLE
Three boys, Abe, Max and Jim had the same number of notes. Abe and Max each had of mix of $20-notes and $10-notes. Abe had 3 $10-notes while Max had 21 $10-notes. Jim had only $20-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Abe and Max's notes? 
3. Max used all his $20-notes to buy a present. He then had $370 less than Jim. How many $20-notes did Jim have?

(a)
The three boys had the same number of notes.
$10-notes have a lower denomination than $20-notes.

Since Jim had only $20-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 21 - 3
= 18

Difference in the value of $20-notes and $10-notes
= 20 - 10
= $10

Difference in the total value of Abe's and Max's notes
= 18 x 10
= $180

(c)
Value of $10-notes that Max had left
= 21 x 10
= $210

Total value that Jim had
= 370 + 210
= $580

Number of $20-notes that Jim had
= 580 ÷ 20
= 29

Answer(s): (a) Jim; (b) $180; (c) 29