PSLE
Three boys, Rio, Bo and Lee had the same number of notes. Rio and Bo each had of mix of $20-notes and $5-notes. Rio had 14 $5-notes while Bo had 24 $5-notes. Lee had only $20-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Rio and Bo's notes? 
3. Bo used all his $20-notes to buy a present. He then had $480 less than Lee. How many $20-notes did Lee have?

(a)
The three boys had the same number of notes.
$5-notes have a lower denomination than $20-notes.

Since Lee had only $20-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 24 - 14
= 10

Difference in the value of $20-notes and $5-notes
= 20 - 5
= $15

Difference in the total value of Rio's and Bo's notes
= 10 x 15
= $150

(c)
Value of $5-notes that Bo had left
= 24 x 5
= $120

Total value that Lee had
= 480 + 120
= $600

Number of $20-notes that Lee had
= 600 ÷ 20
= 30

Answer(s): (a) Lee; (b) $150; (c) 30