PSLE
Three men, Lee, Rey and Joe had the same number of notes. Rey and Lee each had of mix of $20-notes and $10-notes. Rey had 6 $10-notes while Lee had 16 $10-notes. Joe had only $20-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Rey and Lee's notes? 
3. Lee used all his $20-notes to buy a souvenir. Joe then had $260 more than Lee. How many $20-notes did Joe have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $20-notes.

Lee had more $10-notes than Rey while Joe had only the $20-notes.  

Since Lee had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 16 - 6
= 10

Difference in the value of $20-note and $10-note
= 20 - 10
= $10

Difference in the total value of Rey's and Lee's notes
= 10 x 10
= $100

(c)
Value of $10-notes that Lee had left
= 16 x 10
= $160

Total value that Joe had
= 260 + 160
= $420

Number of $20-notes that Joe had
= 420 ÷ 20
= 21

Answer(s): (a) Lee; (b) $100; (c) 21