PSLE
Three men, Ace, Lee and Ty had the same number of notes. Lee and Ace each had of mix of $50-notes and $20-notes. Lee had 5 $20-notes while Ace had 12 $20-notes. Ty had only $50-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Lee and Ace's notes? 
3. Ace used all his $50-notes to buy a gift. Ty then had $1210 more than Ace. How many $50-notes did Ty have?

(a)
The three men had the same number of notes.
$20-notes have a lower denomination than $50-notes.

Ace had more $20-notes than Lee while Ty had only the $50-notes.  

Since Ace had the most number of $20-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 12 - 5
= 7

Difference in the value of $50-note and $20-note
= 50 - 20
= $30

Difference in the total value of Lee's and Ace's notes
= 7 x 30
= $210

(c)
Value of $20-notes that Ace had left
= 12 x 20
= $240

Total value that Ty had
= 1210 + 240
= $1450

Number of $50-notes that Ty had
= 1450 ÷ 50
= 29

Answer(s): (a) Ace; (b) $210; (c) 29