PSLE
Three boys, Abe, Ray and Bo had the same number of notes. Abe and Ray each had of mix of $20-notes and $2-notes. Abe had 7 $2-notes while Ray had 13 $2-notes. Bo had only $20-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Abe and Ray's notes? 
3. Ray used all his $20-notes to buy a present. He then had $534 less than Bo. How many $20-notes did Bo have?

(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $20-notes.

Since Bo had only $20-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 13 - 7
= 6

Difference in the value of $20-notes and $2-notes
= 20 - 2
= $18

Difference in the total value of Abe's and Ray's notes
= 6 x 18
= $108

(c)
Value of $2-notes that Ray had left
= 13 x 2
= $26

Total value that Bo had
= 534 + 26
= $560

Number of $20-notes that Bo had
= 560 ÷ 20
= 28

Answer(s): (a) Bo; (b) $108; (c) 28