PSLE
Three boys, Ian, Abe and Bo had the same number of notes. Ian and Abe each had of mix of $5-notes and $2-notes. Ian had 8 $2-notes while Abe had 13 $2-notes. Bo had only $5-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Ian and Abe's notes? 
3. Abe used all his $5-notes to buy a present. He then had $94 less than Bo. How many $5-notes did Bo have?

(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $5-notes.

Since Bo had only $5-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 13 - 8
= 5

Difference in the value of $5-notes and $2-notes
= 5 - 2
= $3

Difference in the total value of Ian's and Abe's notes
= 5 x 3
= $15

(c)
Value of $2-notes that Abe had left
= 13 x 2
= $26

Total value that Bo had
= 94 + 26
= $120

Number of $5-notes that Bo had
= 120 ÷ 5
= 24

Answer(s): (a) Bo; (b) $15; (c) 24