PSLE
Three men, Lee, Abe and Kit had the same number of notes. Abe and Lee each had of mix of $20-notes and $10-notes. Abe had 13 $10-notes while Lee had 19 $10-notes. Kit had only $20-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Abe and Lee's notes? 
3. Lee used all his $20-notes to buy a present. Kit then had $390 more than Lee. How many $20-notes did Kit have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $20-notes.

Lee had more $10-notes than Abe while Kit had only the $20-notes.  

Since Lee had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 19 - 13
= 6

Difference in the value of $20-note and $10-note
= 20 - 10
= $10

Difference in the total value of Abe's and Lee's notes
= 6 x 10
= $60

(c)
Value of $10-notes that Lee had left
= 19 x 10
= $190

Total value that Kit had
= 390 + 190
= $580

Number of $20-notes that Kit had
= 580 ÷ 20
= 29

Answer(s): (a) Lee; (b) $60; (c) 29