PSLE
Three men, Ray, Ace and Kai had the same number of notes. Ace and Ray each had of mix of $20-notes and $10-notes. Ace had 4 $10-notes while Ray had 13 $10-notes. Kai had only $20-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Ace and Ray's notes? 
3. Ray used all his $20-notes to buy a souvenir. Kai then had $230 more than Ray. How many $20-notes did Kai have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $20-notes.

Ray had more $10-notes than Ace while Kai had only the $20-notes.  

Since Ray had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 13 - 4
= 9

Difference in the value of $20-note and $10-note
= 20 - 10
= $10

Difference in the total value of Ace's and Ray's notes
= 9 x 10
= $90

(c)
Value of $10-notes that Ray had left
= 13 x 10
= $130

Total value that Kai had
= 230 + 130
= $360

Number of $20-notes that Kai had
= 360 ÷ 20
= 18

Answer(s): (a) Ray; (b) $90; (c) 18