PSLE
Three men, Abe, Ken and Sam had the same number of notes. Ken and Abe each had of mix of $20-notes and $10-notes. Ken had 3 $10-notes while Abe had 11 $10-notes. Sam had only $20-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Ken and Abe's notes? 
3. Abe used all his $20-notes to buy a souvenir. Sam then had $470 more than Abe. How many $20-notes did Sam have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $20-notes.

Abe had more $10-notes than Ken while Sam had only the $20-notes.  

Since Abe had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 11 - 3
= 8

Difference in the value of $20-note and $10-note
= 20 - 10
= $10

Difference in the total value of Ken's and Abe's notes
= 8 x 10
= $80

(c)
Value of $10-notes that Abe had left
= 11 x 10
= $110

Total value that Sam had
= 470 + 110
= $580

Number of $20-notes that Sam had
= 580 ÷ 20
= 29

Answer(s): (a) Abe; (b) $80; (c) 29