PSLE
Three boys, Lee, Kai and Jed had the same number of notes. Lee and Kai each had of mix of $20-notes and $10-notes. Lee had 8 $10-notes while Kai had 13 $10-notes. Jed had only $20-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Lee and Kai's notes? 
3. Kai used all his $20-notes to buy a gift. He then had $470 less than Jed. How many $20-notes did Jed have?

(a)
The three boys had the same number of notes.
$10-notes have a lower denomination than $20-notes.

Since Jed had only $20-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 13 - 8
= 5

Difference in the value of $20-notes and $10-notes
= 20 - 10
= $10

Difference in the total value of Lee's and Kai's notes
= 5 x 10
= $50

(c)
Value of $10-notes that Kai had left
= 13 x 10
= $130

Total value that Jed had
= 470 + 130
= $600

Number of $20-notes that Jed had
= 600 ÷ 20
= 30

Answer(s): (a) Jed; (b) $50; (c) 30