PSLE
Three men, Abe, Jed and Dan had the same number of notes. Jed and Abe each had of mix of $50-notes and $10-notes. Jed had 9 $10-notes while Abe had 16 $10-notes. Dan had only $50-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Jed and Abe's notes? 
3. Abe used all his $50-notes to buy a souvenir. Dan then had $890 more than Abe. How many $50-notes did Dan have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $50-notes.

Abe had more $10-notes than Jed while Dan had only the $50-notes.  

Since Abe had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 16 - 9
= 7

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Difference in the total value of Jed's and Abe's notes
= 7 x 40
= $280

(c)
Value of $10-notes that Abe had left
= 16 x 10
= $160

Total value that Dan had
= 890 + 160
= $1050

Number of $50-notes that Dan had
= 1050 ÷ 50
= 21

Answer(s): (a) Abe; (b) $280; (c) 21