PSLE
Three boys, Kai, Bo and Eli had the same number of notes. Kai and Bo each had of mix of $10-notes and $5-notes. Kai had 3 $5-notes while Bo had 13 $5-notes. Eli had only $10-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Kai and Bo's notes? 
3. Bo used all his $10-notes to buy a gift. He then had $165 less than Eli. How many $10-notes did Eli have?

(a)
The three boys had the same number of notes.
$5-notes have a lower denomination than $10-notes.

Since Eli had only $10-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 13 - 3
= 10

Difference in the value of $10-notes and $5-notes
= 10 - 5
= $5

Difference in the total value of Kai's and Bo's notes
= 10 x 5
= $50

(c)
Value of $5-notes that Bo had left
= 13 x 5
= $65

Total value that Eli had
= 165 + 65
= $230

Number of $10-notes that Eli had
= 230 ÷ 10
= 23

Answer(s): (a) Eli; (b) $50; (c) 23