PSLE
Three men, Ari, Nat and Jed had the same number of notes. Nat and Ari each had of mix of $50-notes and $10-notes. Nat had 7 $10-notes while Ari had 17 $10-notes. Jed had only $50-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Nat and Ari's notes? 
3. Ari used all his $50-notes to buy a present. Jed then had $1130 more than Ari. How many $50-notes did Jed have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $50-notes.

Ari had more $10-notes than Nat while Jed had only the $50-notes.  

Since Ari had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 17 - 7
= 10

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Difference in the total value of Nat's and Ari's notes
= 10 x 40
= $400

(c)
Value of $10-notes that Ari had left
= 17 x 10
= $170

Total value that Jed had
= 1130 + 170
= $1300

Number of $50-notes that Jed had
= 1300 ÷ 50
= 26

Answer(s): (a) Ari; (b) $400; (c) 26