PSLE
Three men, Rio, Ned and Sam had the same number of notes. Ned and Rio each had of mix of $50-notes and $10-notes. Ned had 4 $10-notes while Rio had 14 $10-notes. Sam had only $50-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Ned and Rio's notes? 
3. Rio used all his $50-notes to buy a present. Sam then had $1110 more than Rio. How many $50-notes did Sam have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $50-notes.

Rio had more $10-notes than Ned while Sam had only the $50-notes.  

Since Rio had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 14 - 4
= 10

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Difference in the total value of Ned's and Rio's notes
= 10 x 40
= $400

(c)
Value of $10-notes that Rio had left
= 14 x 10
= $140

Total value that Sam had
= 1110 + 140
= $1250

Number of $50-notes that Sam had
= 1250 ÷ 50
= 25

Answer(s): (a) Rio; (b) $400; (c) 25