PSLE
Three men, Ben, Ace and Lon had the same number of notes. Ace and Ben each had of mix of $50-notes and $10-notes. Ace had 6 $10-notes while Ben had 20 $10-notes. Lon had only $50-notes.

1. Of the three men, who had the least money? 
2. What was the difference in the total value of Ace and Ben's notes? 
3. Ben used all his $50-notes to buy a gift. Lon then had $1250 more than Ben. How many $50-notes did Lon have?

(a)
The three men had the same number of notes.
$10-notes have a lower denomination than $50-notes.

Ben had more $10-notes than Ace while Lon had only the $50-notes.  

Since Ben had the most number of $10-notes, he had the least money.

(b)
Difference in the number of notes of different values
= 20 - 6
= 14

Difference in the value of $50-note and $10-note
= 50 - 10
= $40

Difference in the total value of Ace's and Ben's notes
= 14 x 40
= $560

(c)
Value of $10-notes that Ben had left
= 20 x 10
= $200

Total value that Lon had
= 1250 + 200
= $1450

Number of $50-notes that Lon had
= 1450 ÷ 50
= 29

Answer(s): (a) Ben; (b) $560; (c) 29