PSLE
Three boys, Ned, Luc and Tom had the same number of notes. Ned and Luc each had of mix of $10-notes and $2-notes. Ned had 5 $2-notes while Luc had 11 $2-notes. Tom had only $10-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Ned and Luc's notes? 
3. Luc used all his $10-notes to buy a gift. He then had $238 less than Tom. How many $10-notes did Tom have?

(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $10-notes.

Since Tom had only $10-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 11 - 5
= 6

Difference in the value of $10-notes and $2-notes
= 10 - 2
= $8

Difference in the total value of Ned's and Luc's notes
= 6 x 8
= $48

(c)
Value of $2-notes that Luc had left
= 11 x 2
= $22

Total value that Tom had
= 238 + 22
= $260

Number of $10-notes that Tom had
= 260 ÷ 10
= 26

Answer(s): (a) Tom; (b) $48; (c) 26