PSLE
Three boys, Jim, Dan and Ace had the same number of notes. Jim and Dan each had of mix of $10-notes and $2-notes. Jim had 6 $2-notes while Dan had 14 $2-notes. Ace had only $10-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Jim and Dan's notes? 
3. Dan used all his $10-notes to buy a present. He then had $262 less than Ace. How many $10-notes did Ace have?

(a)
The three boys had the same number of notes.
$2-notes have a lower denomination than $10-notes.

Since Ace had only $10-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 14 - 6
= 8

Difference in the value of $10-notes and $2-notes
= 10 - 2
= $8

Difference in the total value of Jim's and Dan's notes
= 8 x 8
= $64

(c)
Value of $2-notes that Dan had left
= 14 x 2
= $28

Total value that Ace had
= 262 + 28
= $290

Number of $10-notes that Ace had
= 290 ÷ 10
= 29

Answer(s): (a) Ace; (b) $64; (c) 29