PSLE Three men, Abe, Dan and Sam had the same number of notes. Dan and Abe each had of mix of $50-notes and $20-notes. Dan had 3 $20-notes while Abe had 11 $20-notes. Sam had only $50-notes.
- Of the three men, who had the least money?
- What was the difference in the total value of Dan and Abe's notes?
- Abe used all his $50-notes to buy a souvenir. Sam then had $830 more than Abe. How many $50-notes did Sam have?
(a)
The three men had the same number of notes.
$20-notes have a lower denomination than $50-notes.
Abe had more $20-notes than Dan while Sam had only the $50-notes.
Since Abe had the most number of $20-notes, he had the least money.
(b)
Difference in the number of notes of different values
= 11 - 3
= 8
Difference in the value of $50-note and $20-note
= 50 - 20
= $30
Difference in the total value of Dan's and Abe's notes
= 8 x 30
= $240
(c)
Value of $20-notes that Abe had left
= 11 x 20
= $220
Total value that Sam had
= 830 + 220
= $1050
Number of $50-notes that Sam had
= 1050 ÷ 50
= 21
Answer(s): (a) Abe; (b) $240; (c) 21