PSLE
Three boys, Roy, Ken and Abe had the same number of notes. Roy and Ken each had of mix of $10-notes and $5-notes. Roy had 7 $5-notes while Ken had 12 $5-notes. Abe had only $10-notes.

1. Of the three boys, who had the most money? 
2. What was the difference in the total value of Roy and Ken's notes? 
3. Ken used all his $10-notes to buy a souvenir. He then had $230 less than Abe. How many $10-notes did Abe have?

(a)
The three boys had the same number of notes.
$5-notes have a lower denomination than $10-notes.

Since Abe had only $10-notes, he had the most money.

(b)
Difference in the number of notes of different values
= 12 - 7
= 5

Difference in the value of $10-notes and $5-notes
= 10 - 5
= $5

Difference in the total value of Roy's and Ken's notes
= 5 x 5
= $25

(c)
Value of $5-notes that Ken had left
= 12 x 5
= $60

Total value that Abe had
= 230 + 60
= $290

Number of $10-notes that Abe had
= 290 ÷ 10
= 29

Answer(s): (a) Abe; (b) $25; (c) 29