PSLE The contestants at a contest are divided in Team A and Team B. The ratio of the number of girls to boys in Team A is 3 : 2. The ratio of the number of girls to boys in Team B is 3 : 1. There are 4 times as many contestants in Team B as in Team A. There are 120 less girls in Team A than Team B. What is the total number of contestants in Team A?
Team A |
Team B |
5 u |
4x5 = 20 u |
Girls |
Boys |
Girls |
Boys |
3 u |
2 u |
3x5 = 15 u |
1x5 = 5 u
|
Total number of contestants in Team A
= 3 u + 2 u
= 5 u
Total number of contestants in Team B
= 4 x 5 u
= 20 u
The total number of contestants in Team B is repeated.
Use LCM to make the total number of contestants in Team B the same.
LCM of 20 and 4 is 20.
Number of less girls in Team A than Team B
= 15 u - 3 u
= 12 u
12 u = 120
1 u = 120 ÷ 12 = 10
Total number of contestants in Team A
= 3 u + 2 u
= 5 u
= 5 x 10
= 50
Answer(s): 50