PSLE The contestants at a contest are divided in Team A and Team B. The ratio of the number of girls to boys in Team A is 4 : 3. The ratio of the number of girls to boys in Team B is 11 : 3. There are 4 times as many contestants in Team B as in Team A. There are 270 more girls in Team B than Team A. What is the total number of boys?
Team A |
Team B |
7 u |
14x2 = 28 u |
Girls |
Boys |
Girls |
Boys |
4 u |
3 u |
11x2 = 22 u |
3x2 = 6 u
|
Total number of contestants in Team A
= 4 u + 3 u
= 7 u
Total number of contestants in Team B
= 4 x 7 u
= 28 u
The total number of contestants in Team B is repeated.
Use LCM to make the total number of contestants in Team B the same.
LCM of 28 and 14 is 28.
Number of more girls in Team B than Team A
= 22 u - 4 u
= 18 u
18 u = 270
1 u = 270 ÷ 18 = 15
Total number of boys
= 3 u + 6 u
= 9 u
= 9 x 15
= 135
Answer(s): 135